The answer to the above code snippet is 35. The value of â€œaâ€ passed to the function is 2 and the value for â€œbâ€ defined in the function f (a) is 3. So the output would be 3^3 + g (2). The function g is defined in the global environment and it takes the value of b as 4(due to lexical scoping in R) not 3 returning a value 2*4= 8 to the function f. The result will be 3^3+8= 35.