We can remove items present in p2 from p1 using isin() method.
import pandas as pd
p1 = pd.Series([2, 4, 6, 8, 10])
p2 = pd.Series([8, 10, 12, 14, 16])
p1[~p1.isin(p2)]
Solution
0 2
1 4
2 6
dtype: int64