A particle is in SHM. When displacement is ‘a‘ potential energy is 8J. When displacement is ‘a‘ potential energy is 18J. What will be the potential energy when displacement is ‘a+b’?(a) 50J(b) 26J(c) 10J(d) 30J
Correct answer is (a) 50JTo explain I would say: 1/2ka^2 = 8 & 1/2kb^2 = 18.We have to find value of 1/2k(a + b) ^2. ∴ 1/2k(a + b)^2 = 8 + 18 + kab = 26+(k*4*6/k) = 26 + 24 = 50J.