What will be the value of temperature of hot reservoir in a carnot cycle, if the temperature of cold reservoir is 25°C, heat absorbed from hot reservoir is 12J and heat rejected to cold reservoir is 4J?(a) 684K(b) 333.33K(c) 894K(d) 433.33K
Correct answer is (c) 894KThe best I can explain: For a carnot cycle: Q2/Q2 = T2/T1.T2 = 12/4 * 298 = 894K.