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File.mismatch method Java12 features

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Java 12 added the following method to compare two files:

public static long mismatch(Path path, Path path2) throws IOException

This method returns the position of the first mismatch or -1L if there is no mismatch.

Two files can have a mismatch in the following scenarios:

If the bytes are not identical. In this case, the position of the first mismatching byte is returned.

File sizes are not identical. In this case, the size of the smaller file is returned.

Example code snippet from IntelliJ Idea is given below:


import java.nio.file.Files;

import java.nio.file.Path;

public class FileMismatchExample {

    public static void main(String[] args) throws IOException {

        Path filePath1 = Files.createTempFile("file1", ".txt");

        Path filePath2 = Files.createTempFile("file2", ".txt");

        Files.writeString(filePath1,"JournalDev Test String");

        Files.writeString(filePath2,"JournalDev Test String");

        long mismatch = Files.mismatch(filePath1, filePath2);

        System.out.println("File Mismatch position... It returns -1 if there is no mismatch");

        System.out.println("Mismatch position in file1 and file2 is >>>>");





        Path filePath3 = Files.createTempFile("file3", ".txt");

        Path filePath4 = Files.createTempFile("file4", ".txt");

        Files.writeString(filePath3,"JournalDev Test String");

        Files.writeString(filePath4," Test String");

        long mismatch2 = Files.mismatch(filePath3, filePath4);

        System.out.println("Mismatch position in file3 and file4 is >>>>");






The output when the above Java Program is compiled and run is:


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