A wire has a young’s modulus of 10^5N/m^2, length 1m & radius 3mm. Assuming a uniform cross sectional area, find the radius of wire after it is under a force of 1N from both ends.
Correct choice is (a) 2.58m
Easiest explanation: Force = 1N. Initial area = πr^2 = 2.82*10^-5m^2.
Stress = Y*Strain
Δl = F/A * l/Y = (1/2.82*10^-5)*(1/10^5) = 0.35m
As volume will remain same (we can also say that product of l & r^2 will be constant as other terms in expression of volume are constants).
1*3^2 = 1.35*R^2
⇒R = 2.58m.
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