Consider the damped SHM of a spring mass system. If the time taken for the amplitude to become half is ‘T’, what is the time taken for mechanical energy to become half?(a) T(b) T/2(c) 2T(d) T/4
The correct answer is (b) T/2The explanation is: Amplitude = Ae^-bt/2m& Energy = 1/2kA^2e^-bt/m. For amplitude to become half, e^-bt/2m = 1/2Or bT/2m = ln(2)Or T = 2m ln(2)/b For energy to become half, e^-bt/m = 1/2Or t = m ln(2)/b = T/2.