A pipe is open at both ends. What should be its length such that it resonates a 10Hz source in the 2nd harmonic? Speed of sound in air = 340m/s.(a) 34m(b) 68m(c) 17m(d) 51m
Right answer is (a) 34mThe best I can explain: For a pipe open at both ends frequency ‘f’ = nv/2L, where n is speed of sound.Given: f = 10 & n=2.∴ 10 = 2*340/2L∴ L = 680/20= 34m.