list = ['a', 'b', 'c', 'd', 'e']
print (list[10:])
The consequence of the above lines of code is []. There won't be any mistake like an IndexError.
You should realize that attempting to bring a part from the rundown utilizing a file that surpasses the part mean (model, endeavoring to get to list[10] as given in the inquiry) would yield an IndexError. Coincidentally, recovering just a cut at the beginning file that outperforms the no. of things in the rundown won't bring about an IndexError. It will simply restore an unfilled rundown.